Solucionar Sd_{1}=40x_{1}y+40x_{1}5+35x_{1}4x_{1}6+50x_{1}2*96

$$S d _ { 1 } = 40 x _ { 1 } y + 40 x _ { 1 } 5 + 35 x _ { 1 } 4 x _ { 1 } 6 + 50 x _ { 1 } 2 \times 96$$

Resolver para S (solución compleja)

$$\left\{\begin{matrix}S=\frac{40x_{1}\left(21x_{1}+y+245\right)}{d_{1}}\text{, }&d_{1}\neq 0\\S\in \mathrm{C}\text{, }&\left(x_{1}=0\text{ or }x_{1}=-\frac{y}{21}-\frac{35}{3}\right)\text{ and }d_{1}=0\end{matrix}\right,$$

Pasos para resolver una ecuación lineal

Multiplica x_{1} y x_{1} para obtener x_{1}^{2}.

$$Sd_{1}=40x_{1}y+40x_{1}\times 5+35x_{1}^{2}\times 4\times 6+50x_{1}\times 2\times 96$$

Multiplica 40 y 5 para obtener 200.

$$Sd_{1}=40x_{1}y+200x_{1}+35x_{1}^{2}\times 4\times 6+50x_{1}\times 2\times 96$$

Multiplica 35 y 4 para obtener 140.

$$Sd_{1}=40x_{1}y+200x_{1}+140x_{1}^{2}\times 6+50x_{1}\times 2\times 96$$

Multiplica 140 y 6 para obtener 840.

$$Sd_{1}=40x_{1}y+200x_{1}+840x_{1}^{2}+50x_{1}\times 2\times 96$$

Multiplica 50 y 2 para obtener 100.

$$Sd_{1}=40x_{1}y+200x_{1}+840x_{1}^{2}+100x_{1}\times 96$$

Multiplica 100 y 96 para obtener 9600.

$$Sd_{1}=40x_{1}y+200x_{1}+840x_{1}^{2}+9600x_{1}$$

Combina 200x_{1} y 9600x_{1} para obtener 9800x_{1}.

$$Sd_{1}=40x_{1}y+9800x_{1}+840x_{1}^{2}$$

La ecuación está en formato estándar.

$$d_{1}S=840x_{1}^{2}+40x_{1}y+9800x_{1}$$

Divide los dos lados por d_{1}.

$$\frac{d_{1}S}{d_{1}}=\frac{40x_{1}\left(21x_{1}+y+245\right)}{d_{1}}$$

Al dividir por d_{1}, se deshace la multiplicación por d_{1}.

$$S=\frac{40x_{1}\left(21x_{1}+y+245\right)}{d_{1}}$$

Resolver para d_1 (solución compleja)

$$\left\{\begin{matrix}d_{1}=\frac{40x_{1}\left(21x_{1}+y+245\right)}{S}\text{, }&S\neq 0\\d_{1}\in \mathrm{C}\text{, }&\left(x_{1}=0\text{ or }x_{1}=-\frac{y}{21}-\frac{35}{3}\right)\text{ and }S=0\end{matrix}\right,$$

Pasos para resolver una ecuación lineal

Multiplica x_{1} y x_{1} para obtener x_{1}^{2}.

$$Sd_{1}=40x_{1}y+40x_{1}\times 5+35x_{1}^{2}\times 4\times 6+50x_{1}\times 2\times 96$$

Multiplica 40 y 5 para obtener 200.

$$Sd_{1}=40x_{1}y+200x_{1}+35x_{1}^{2}\times 4\times 6+50x_{1}\times 2\times 96$$

Multiplica 35 y 4 para obtener 140.

$$Sd_{1}=40x_{1}y+200x_{1}+140x_{1}^{2}\times 6+50x_{1}\times 2\times 96$$

Multiplica 140 y 6 para obtener 840.

$$Sd_{1}=40x_{1}y+200x_{1}+840x_{1}^{2}+50x_{1}\times 2\times 96$$

Multiplica 50 y 2 para obtener 100.

$$Sd_{1}=40x_{1}y+200x_{1}+840x_{1}^{2}+100x_{1}\times 96$$

Multiplica 100 y 96 para obtener 9600.

$$Sd_{1}=40x_{1}y+200x_{1}+840x_{1}^{2}+9600x_{1}$$

Combina 200x_{1} y 9600x_{1} para obtener 9800x_{1}.

$$Sd_{1}=40x_{1}y+9800x_{1}+840x_{1}^{2}$$

La ecuación está en formato estándar.

$$Sd_{1}=840x_{1}^{2}+40x_{1}y+9800x_{1}$$

Divide los dos lados por S.

$$\frac{Sd_{1}}{S}=\frac{40x_{1}\left(21x_{1}+y+245\right)}{S}$$

Al dividir por S, se deshace la multiplicación por S.

$$d_{1}=\frac{40x_{1}\left(21x_{1}+y+245\right)}{S}$$

Resolver para S

$$\left\{\begin{matrix}S=\frac{40x_{1}\left(21x_{1}+y+245\right)}{d_{1}}\text{, }&d_{1}\neq 0\\S\in \mathrm{R}\text{, }&\left(x_{1}=0\text{ or }x_{1}=-\frac{y}{21}-\frac{35}{3}\right)\text{ and }d_{1}=0\end{matrix}\right,$$

Pasos para resolver una ecuación lineal

Multiplica x_{1} y x_{1} para obtener x_{1}^{2}.

$$Sd_{1}=40x_{1}y+40x_{1}\times 5+35x_{1}^{2}\times 4\times 6+50x_{1}\times 2\times 96$$

Multiplica 40 y 5 para obtener 200.

$$Sd_{1}=40x_{1}y+200x_{1}+35x_{1}^{2}\times 4\times 6+50x_{1}\times 2\times 96$$

Multiplica 35 y 4 para obtener 140.

$$Sd_{1}=40x_{1}y+200x_{1}+140x_{1}^{2}\times 6+50x_{1}\times 2\times 96$$

Multiplica 140 y 6 para obtener 840.

$$Sd_{1}=40x_{1}y+200x_{1}+840x_{1}^{2}+50x_{1}\times 2\times 96$$

Multiplica 50 y 2 para obtener 100.

$$Sd_{1}=40x_{1}y+200x_{1}+840x_{1}^{2}+100x_{1}\times 96$$

Multiplica 100 y 96 para obtener 9600.

$$Sd_{1}=40x_{1}y+200x_{1}+840x_{1}^{2}+9600x_{1}$$

Combina 200x_{1} y 9600x_{1} para obtener 9800x_{1}.

$$Sd_{1}=40x_{1}y+9800x_{1}+840x_{1}^{2}$$

La ecuación está en formato estándar.

$$d_{1}S=840x_{1}^{2}+40x_{1}y+9800x_{1}$$

Divide los dos lados por d_{1}.

$$\frac{d_{1}S}{d_{1}}=\frac{40x_{1}\left(21x_{1}+y+245\right)}{d_{1}}$$

Al dividir por d_{1}, se deshace la multiplicación por d_{1}.

$$S=\frac{40x_{1}\left(21x_{1}+y+245\right)}{d_{1}}$$

Resolver para d_1

$$\left\{\begin{matrix}d_{1}=\frac{40x_{1}\left(21x_{1}+y+245\right)}{S}\text{, }&S\neq 0\\d_{1}\in \mathrm{R}\text{, }&\left(x_{1}=0\text{ or }x_{1}=-\frac{y}{21}-\frac{35}{3}\right)\text{ and }S=0\end{matrix}\right,$$

Pasos para resolver una ecuación lineal

Multiplica x_{1} y x_{1} para obtener x_{1}^{2}.

$$Sd_{1}=40x_{1}y+40x_{1}\times 5+35x_{1}^{2}\times 4\times 6+50x_{1}\times 2\times 96$$

Multiplica 40 y 5 para obtener 200.

$$Sd_{1}=40x_{1}y+200x_{1}+35x_{1}^{2}\times 4\times 6+50x_{1}\times 2\times 96$$

Multiplica 35 y 4 para obtener 140.

$$Sd_{1}=40x_{1}y+200x_{1}+140x_{1}^{2}\times 6+50x_{1}\times 2\times 96$$

Multiplica 140 y 6 para obtener 840.

$$Sd_{1}=40x_{1}y+200x_{1}+840x_{1}^{2}+50x_{1}\times 2\times 96$$

Multiplica 50 y 2 para obtener 100.

$$Sd_{1}=40x_{1}y+200x_{1}+840x_{1}^{2}+100x_{1}\times 96$$

Multiplica 100 y 96 para obtener 9600.

$$Sd_{1}=40x_{1}y+200x_{1}+840x_{1}^{2}+9600x_{1}$$

Combina 200x_{1} y 9600x_{1} para obtener 9800x_{1}.

$$Sd_{1}=40x_{1}y+9800x_{1}+840x_{1}^{2}$$

La ecuación está en formato estándar.

$$Sd_{1}=840x_{1}^{2}+40x_{1}y+9800x_{1}$$

Divide los dos lados por S.

$$\frac{Sd_{1}}{S}=\frac{40x_{1}\left(21x_{1}+y+245\right)}{S}$$

Al dividir por S, se deshace la multiplicación por S.

$$d_{1}=\frac{40x_{1}\left(21x_{1}+y+245\right)}{S}$$