Solucionar 18*10^-2*(10^-2+1)

$$18 \cdot 10 ^ { - 2 } \cdot ( 10 ^ { - 2 } + 1 )$$

Calcular

$$\frac{909}{5000}=0,1818$$

Pasos de la solución

Calcula 10 a la potencia de -2 y obtiene \frac{1}{100}.

$$18\times \frac{1}{100}\left(10^{-2}+1\right)$$

Multiplica 18 y \frac{1}{100} para obtener \frac{9}{50}.

$$\frac{9}{50}\left(10^{-2}+1\right)$$

Calcula 10 a la potencia de -2 y obtiene \frac{1}{100}.

$$\frac{9}{50}\left(\frac{1}{100}+1\right)$$

Suma \frac{1}{100} y 1 para obtener \frac{101}{100}.

$$\frac{9}{50}\times \frac{101}{100}$$

Multiplica \frac{9}{50} y \frac{101}{100} para obtener \frac{909}{5000}.

$$\frac{909}{5000}$$

Factorizar

$$\frac{3 ^ {2} \cdot 101}{2 ^ {3} \cdot 5 ^ {4}} = 0,1818$$