Solucionar 1500-1397 | Microsoft Math Solver

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1500 - 1397

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103

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103

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Cuestionario

1500 - 1397

Problemas similares de búsqueda web

https://brainly.com/question/8241353

a 144.12is the answer

From the definition of

f (s) = \sum_{n = 1}^{\infty} \frac{μ ( n ) - μ ( n + 1 )}{n ^{s}}

1 - f (s) = S (s) + T (s)

https://math.stackexchange.com/questions/2097555/from-the-definition-of-fs-sum-n-1-infty-frac-mun-mun1ns-to-an

Numerically it now works, however after simplifying your

S (s)

T (s)

functions I get:

1 - f (s) = \sum_{n \geq 1} (\frac{1}{n ^{s}} - \frac{1}{( n + 1 ) ^{s}}) \cdot (\frac{M ( n )}{n} + \sum_{k = 1}^{n - 1} \frac{M ( k )}{k ( k - 1 )} - μ (n + 1) - \sum_{m = 1}^{n} \frac{μ ( m )}{m})

There is a relationship between the expected number of tickets sold for a raffle and the dollar value of the prize for the raffle. The equation T - 6P = 100 describes this relationship, where T is ...

https://brainly.com/question/1807747

Given:T - 6P = 100T = tickets soldP = dollar value of the raffle prize.Ticket sales = 1,900, what is P?T - 6P = 1001,900 - 6P = 100- 6P = 100 - 1900- 6P = -1800- 6P \/ -6 = -1800\/-6P = 300 \u00a0The ...

13 g + 2 (4 k - g)

http://www.tiger-algebra.com/drill/13g_2(4k-g)/

13g+2(4k-g) Final result : 11g + 8k Step by step solution : Step 1 :Equation at the end of step 1 : 13g + 2 • (4k - g) Step 2 :Final result : 11g + 8k Processing ends successfully

13 k + 5 = k - 7

http://www.tiger-algebra.com/drill/13k_5=k-7/

13k+5=k-7 One solution was found : k = -1 Rearrange: Rearrange the equation by subtracting what is to the right of the equal sign from both sides of the equation : ...

The integer values of

\sum_{d ∣ n} \frac{σ ( n / d ) ^{d}}{d}

https://math.stackexchange.com/questions/2272764/the-integer-values-of-sum-dn-frac-sigman-ddd

f (n) = \sum_{d ∣ n} \frac{σ ( n / d ) ^{d}}{d}

p, q

are two different primes then

f (p q) = σ (p q) + \frac{p ( p + 1 ) ^{q} + q ( q + 1 ) ^{p} + 1}{p q}

f (p q) \in Z

p (p + 1)^{q} + q (q + 1)^{p} + 1 \equiv 0 m o d p

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103

Resta 1397 de 1500 para obtener 103.

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Ecuación simultánea

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