Solucionar -000002(x-12)^2(x-17)(x-9)(x-2)(x+4)(x^2+3)

$$- 000002 ( x - 12 ) ^ { 2 } ( x - 17 ) ( x - 9 ) ( x - 2 ) ( x + 4 ) ( x ^ { 2 } + 3 )$$

Calcular

$$0$$

Pasos de la solución

Multiplica 0 y 0 para obtener 0.

$$0\times 0\times 0\times 0\times 2\left(x-12\right)^{2}\left(x-17\right)\left(x-9\right)\left(x-2\right)\left(x+4\right)\left(x^{2}+3\right)$$

Multiplica 0 y 0 para obtener 0.

$$0\times 0\times 0\times 2\left(x-12\right)^{2}\left(x-17\right)\left(x-9\right)\left(x-2\right)\left(x+4\right)\left(x^{2}+3\right)$$

Multiplica 0 y 0 para obtener 0.

$$0\times 0\times 2\left(x-12\right)^{2}\left(x-17\right)\left(x-9\right)\left(x-2\right)\left(x+4\right)\left(x^{2}+3\right)$$

Multiplica 0 y 0 para obtener 0.

$$0\times 2\left(x-12\right)^{2}\left(x-17\right)\left(x-9\right)\left(x-2\right)\left(x+4\right)\left(x^{2}+3\right)$$

Multiplica 0 y 2 para obtener 0.

$$0\left(x-12\right)^{2}\left(x-17\right)\left(x-9\right)\left(x-2\right)\left(x+4\right)\left(x^{2}+3\right)$$

Utilice el teorema binomial \left(a-b\right)^{2}=a^{2}-2ab+b^{2} para expandir \left(x-12\right)^{2}.

$$0\left(x^{2}-24x+144\right)\left(x-17\right)\left(x-9\right)\left(x-2\right)\left(x+4\right)\left(x^{2}+3\right)$$

Cualquier valor multiplicado por cero da como resultado cero.

$$0$$

Factorizar

$$0$$