Solucionar tan^2θ-sec^2θ=

$$\tan ^ { 2 } \theta - \sec ^ { 2 } \theta =$$

Factorizar

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Pasos de la solución

La diferencia de los cuadrados se puede factorizar mediante la regla: a^{2}-b^{2}=\left(a-b\right)\left(a+b\right).

$$\left(\tan(\theta )-\frac{1}{\cos(\theta )}\right)\left(\tan(\theta )+\frac{1}{\cos(\theta )}\right)$$

Piense en \tan(\theta )-\frac{1}{\cos(\theta )}. Simplifica \frac{1}{\cos(\theta )}.

$$\frac{\sin(\theta )-1}{\cos(\theta )}$$

Piense en \tan(\theta )+\frac{1}{\cos(\theta )}. Simplifica \frac{1}{\cos(\theta )}.

$$\frac{\sin(\theta )+1}{\cos(\theta )}$$

Vuelva a escribir la expresión factorizada completa.

$$\left(\sin(\theta )-1\right)\left(\sin(\theta )+1\right)\times \left(\frac{1}{\cos(\theta )}\right)^{2}$$

Calcular

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