Solucionar sigma_x^2=(-2-0)^alpha*4/9+(0*0)^2*3/9+(1*0)^2+2/9=

$$\sigma _ { x } ^ { 2 } = ( - 2 - 0 ) ^ { \alpha } \times \frac { 4 } { 9 } + ( 0 \times 0 ) ^ { 2 } \times \frac { 3 } { 9 } + ( 1 \times 0 ) ^ { 2 } + \frac { 2 } { 9 } =$$

Resolver para α

$$\alpha =\log_{2}\left(\frac{9\sigma _{x}^{2}}{4}-\frac{1}{2}\right)$$

$$Numerator(\log_{2}\left(\frac{9\sigma _{x}^{2}}{4}-\frac{1}{2}\right))\text{bmod}2=0\text{ and }Denominator(\log_{2}\left(\frac{9\sigma _{x}^{2}}{4}-\frac{1}{2}\right))\text{bmod}2=1\text{ and }|\sigma _{x}|>\frac{\sqrt{2}}{3}$$

Resolver para σ_x

$$\sigma _{x}=\frac{\sqrt{\left(-2\right)^{\alpha +2}+2}}{3}$$

$$\sigma _{x}=-\frac{\sqrt{\left(-2\right)^{\alpha +2}+2}}{3}\text{, }Denominator(\alpha )\text{bmod}2=1\text{ and }\left(-2\right)^{\alpha }\geq -\frac{1}{2}$$