Solucionar ∫ 2x+ygeq6

$$\int 2 x + y \geq 6$$

Resolver para x

$$\left\{\begin{matrix}x\in \mathrm{R}\text{, }&С\leq -y^{2}\\x\in (-\infty,\frac{-\sqrt{y^{2}+С}-y}{2}]\cup [\frac{\sqrt{y^{2}+С}-y}{2},\infty)\text{, }&С\geq -y^{2}\end{matrix}\right,$$

Resolver para y

$$\left\{\begin{matrix}y\geq -x-\frac{С}{x}+\frac{6}{x}\text{, }&x>0\\y\in \mathrm{R}\text{, }&С\geq 6\text{ and }x=0\\y=-x-\frac{С}{x}+\frac{6}{x}\text{, }&С\geq 6\text{ or }x\neq 0\\y\leq -x-\frac{С}{x}+\frac{6}{x}\text{, }&x<0\\y\leq \text{Indeterminate}\text{, }&\left(\text{Indeterminate}<-x-\frac{С}{x}+\frac{6}{x}\text{ and }x<0\right)\text{ or }\left(С_{1}\geq 6\text{ and }x\leq 0\right)\end{matrix}\right,$$