Solucionar 1/10left(left(9-83right)^2*2+left(8-83right)^2*6+left(10-83right)^2+left(7-83right)^2right)

$$\frac{ 1 }{ 10 } \left( { \left(9-83 \right) }^{ 2 } \times 2+ { \left(8-83 \right) }^{ 2 } \times 6+ { \left(10-83 \right) }^{ 2 } + { \left(7-83 \right) }^{ 2 } \right)$$

Calcular

$$\frac{55807}{10}=5580,7$$

Pasos de la solución

Resta 83 de 9 para obtener -74.

$$\frac{1}{10}\left(\left(-74\right)^{2}\times 2+\left(8-83\right)^{2}\times 6+\left(10-83\right)^{2}+\left(7-83\right)^{2}\right)$$

Calcula -74 a la potencia de 2 y obtiene 5476.

$$\frac{1}{10}\left(5476\times 2+\left(8-83\right)^{2}\times 6+\left(10-83\right)^{2}+\left(7-83\right)^{2}\right)$$

Multiplica 5476 y 2 para obtener 10952.

$$\frac{1}{10}\left(10952+\left(8-83\right)^{2}\times 6+\left(10-83\right)^{2}+\left(7-83\right)^{2}\right)$$

Resta 83 de 8 para obtener -75.

$$\frac{1}{10}\left(10952+\left(-75\right)^{2}\times 6+\left(10-83\right)^{2}+\left(7-83\right)^{2}\right)$$

Calcula -75 a la potencia de 2 y obtiene 5625.

$$\frac{1}{10}\left(10952+5625\times 6+\left(10-83\right)^{2}+\left(7-83\right)^{2}\right)$$

Multiplica 5625 y 6 para obtener 33750.

$$\frac{1}{10}\left(10952+33750+\left(10-83\right)^{2}+\left(7-83\right)^{2}\right)$$

Suma 10952 y 33750 para obtener 44702.

$$\frac{1}{10}\left(44702+\left(10-83\right)^{2}+\left(7-83\right)^{2}\right)$$

Resta 83 de 10 para obtener -73.

$$\frac{1}{10}\left(44702+\left(-73\right)^{2}+\left(7-83\right)^{2}\right)$$

Calcula -73 a la potencia de 2 y obtiene 5329.

$$\frac{1}{10}\left(44702+5329+\left(7-83\right)^{2}\right)$$

Suma 44702 y 5329 para obtener 50031.

$$\frac{1}{10}\left(50031+\left(7-83\right)^{2}\right)$$

Resta 83 de 7 para obtener -76.

$$\frac{1}{10}\left(50031+\left(-76\right)^{2}\right)$$

Calcula -76 a la potencia de 2 y obtiene 5776.

$$\frac{1}{10}\left(50031+5776\right)$$

Suma 50031 y 5776 para obtener 55807.

$$\frac{1}{10}\times 55807$$

Multiplica \frac{1}{10} y 55807 para obtener \frac{55807}{10}.

$$\frac{55807}{10}$$

Factorizar

$$\frac{55807}{2 \cdot 5} = 5580\frac{7}{10} = 5580,7$$