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Fun + improving skills = win!
Topics
Pre-Algebra
Mean
Mode
Greatest Common Factor
Least Common Multiple
Order of Operations
Fractions
Mixed Fractions
Prime Factorization
Exponents
Radicals
Algebra
Combine Like Terms
Solve for a Variable
Factor
Expand
Evaluate Fractions
Linear Equations
Quadratic Equations
Inequalities
Systems of Equations
Matrices
Trigonometry
Simplify
Evaluate
Graphs
Solve Equations
Calculus
Derivatives
Integrals
Limits
Algebra Inputs
Trigonometry Inputs
Calculus Inputs
Matrix Inputs
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-2%20%3C%203x%2B2%20%3C%208
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-2
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-2
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5 problems similar to:
-2%20%3C%203x%2B2%20%3C%208
Similar Problems from Web Search
-125x3+1.875x4-2.5x2+6.25x5
https://www.tiger-algebra.com/drill/-125x3_1.875x4-2.5x2_6.25x5/
-125x3+(1875/1000)x4-(25/10)x2+(625/100)x5 Final result : 5x2 • (10x3 + 3x2 - 200x - 4) ————————————————————————————— 8 Reformatting the input : Changes made to your input should not affect the ...
How do you solve \displaystyle-{7}{x}+{5}={3}+{12}+{9}{x}={16}{x}-{3}{x}+{6}-{2}+{12} ?
https://socratic.org/questions/how-do-you-solve-7x-5-3-12-9x-16x-3x-6-2-12
As written there is no solution Explanation: Let's simplify all the expressions: \displaystyle-{7}{x}+{5}={3}+{12}+{9}{x}={16}{x}-{3}{x}+{6}-{2}+{12} \displaystyle-{7}{x}+{5}={9}{x}+{15}={13}{x}+{16} ...
Modulus Problem: |x+1| - |x| + 3|x-1| -2|x-2| = x+2 [closed]
https://math.stackexchange.com/questions/1382711/modulus-problem-x1-x-3x-1-2x-2-x2
Addendum: The first case. For x\le 1 as mentioned ALL of the expressions in the |\cdot| are negative, so the expression takes the form: -(x+1)+x-3(x-1)+2(x-2) =-x-2 after tidying up. This is ...
0.0625+x=0.0625(3.3-2x)(3.3-2x)
https://www.tiger-algebra.com/drill/0.0625_x=0.0625(3.3-2x)(3.3-2x)/
(625/10000)+x=(625/10000)((33/10)-2x)((33/10)-2x) Two solutions were found : x =(-2920-√6944000)/-800=73/20+1/10√ 1085 = 6.944 x =(-2920+√6944000)/-800=73/20-1/10√ 1085 = 0.356 Reformatting ...
6x5+13x4-20x3-55x2-16x+12=0
https://www.tiger-algebra.com/drill/6x5_13x4-20x3-55x2-16x_12=0/
6x5+13x4-20x3-55x2-16x+12=0 5 solutions were found : x = 2 x = 1/3 = 0.333 x = -3/2 = -1.500 x = -1 x = -2 Reformatting the input : Changes made to your input should not affect the ...
Show I=\{sf\mid s\in \mathbb Z_{11}[x]\} matches J=\{h \in \mathbb Z_{11}[x] \mid h(1) = h(-2) = 0\}.
https://math.stackexchange.com/questions/326504/show-i-sf-mid-s-in-mathbb-z-11x-matches-j-h-in-mathbb-z-11x
Note that F=\mathbb{Z}_{11} is a field (although actually, the only thing you need is that -3=8 is invertible. Then recall that for a polynomial f\in F[X] and a\in F f(a)=0\quad\Leftrightarrow \quad f(x)=(x-a)g(x) ...
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