Løs F=5x^2+3x+1*x^2+4x-1 | Microsoft Problemløser til matematik

Løs for F

F=6x^{2}+7x-1

Løsningsvejledning

F = 5 x ^ { 2 } + 3 x + 1 \cdot x ^ { 2 } + 4 x - 1

Kombiner 5x^{2} og 1x^{2} for at få 6x^{2}.

F=6x^{2}+3x+4x-1

Kombiner 3x og 4x for at få 7x.

F=6x^{2}+7x-1

Løs for x (complex solution)

x=\frac{\sqrt{24F+73}-7}{12}

x=\frac{-\sqrt{24F+73}-7}{12}

Løs for x

x=\frac{\sqrt{24F+73}-7}{12}

x=\frac{-\sqrt{24F+73}-7}{12}\text{, }F\geq -\frac{73}{24}

Graf

Quiz

Algebra

5 problemer svarende til:

F = 5 x ^ { 2 } + 3 x + 1 \cdot x ^ { 2 } + 4 x - 1

Lignende problemer fra websøgning

How do you integrate \displaystyle{\left({x}^{{2}}+{x}-{1}\right)}\cdot{\left({x}^{{2}}+{x}-{1}\right)} ?

https://socratic.org/questions/how-do-you-integrate-x-2-x-1-x-2-x-1

\displaystyle\int{\left({x}^{{2}}+{x}-{1}\right)}{\left({x}^{{2}}+{x}-{1}\right)}{\left.{d}{x}\right.}=\frac{{x}^{{5}}}{{5}}+\frac{{x}^{{4}}}{{2}}-\frac{{x}^{{3}}}{{3}}-{x}^{{2}}+{x} ...

How do you multiply \displaystyle{\left({4.8}{x}{10}^{{2}}\right)}\cdot{\left({2.101}{x}{10}^{{3}}\right)} ?

https://socratic.org/questions/how-do-you-multiply-4-8-x-10-2-2-101-x-10-3

Alan P. Apr 14, 2015 \displaystyle{\left({4.8}\times{10}^{{2}}\right)}\cdot{\left({2.101}\times{10}^{{3}}\right)} \displaystyle={\left({4.8}\times{2.101}\right)}\times{\left({10}^{{2}}\times{10}^{{3}}\right)} ...

How do you differentiate \displaystyle{f{{\left({x}\right)}}}={\left({x}^{{2}}+{4}{x}\right)}\cdot{\left({x}^{{3}}+{2}{x}+{1}\right)} using the product rule?

https://socratic.org/questions/how-do-you-differentiate-f-x-x-2-4x-x-3-2x-1-using-the-product-rule

Product rule states that for \displaystyle{y}={f{{\left({x}\right)}}}{g{{\left({x}\right)}}} , then \displaystyle\frac{{{\left.{d}{y}\right.}}}{{{\left.{d}{x}\right.}}}={f}'{\left({x}\right)}{g{{\left({x}\right)}}}+{f{{\left({x}\right)}}}{g}'{\left({x}\right)} ...

Why does 1+x^2+x^4+x^6+x^8+\cdots sum to \frac{1}{1-x^2}?

https://www.quora.com/Why-does-1-x-2-x-4-x-6-x-8-cdots-sum-to-frac-1-1-x-2

The goal of this answer is to address the essence of the matter at hand and to arm the reader with an ability to solve similar problems on her/his own. So - why. Because the arithmetic addition ...

Calculate GCD(x^4+x+1,x^3+x^2) and a Bezout Identity in \mathbb{F_2}

https://math.stackexchange.com/q/637531

This is easy when using the augmented-matrix form of the extended Euclidean algorithm. \begin{eqnarray} (1)&& &&x^4\!+x+1 \,&=&\, \left<\,\color{#c00}1,\color{#0a0}0\,\right>\ \ \ {\rm i.e.}\,\ \ x^4\!+x+1 = \color{#c00}1\cdot (x^4\!+x+1) + \color{#0a0}0\cdot(x^3\!+x^2)\\ (2)&& && x^3\!+x^2 \,&=&\, \left<\,\color{#c00}0,\color{#0a0}1\,\right>\ \ \ {\rm i.e.}\,\quad\ \ \ x^3\!+x^2 = \color{#c00}0\cdot (x^4\!+x+1) + \color{#0a0}1\cdot(x^3\!+x^2)\\ (3)&=&(1)-x\cdot (2)\quad && x^3\!+x+1 \,&=&\, \left<\,1,\,x\,\right>\\ (4)&=&(2)-(3)\quad && x^2\!+x+1 \,&=&\, \left<\,1,\,x+1\,\right>\\ (5)&=&(2)-x\cdot(4)\quad &&\qquad\quad\ \ \ x \,&=&\, \left<x,\,x^2+x+1\right>\\ (6)&=&(4)-(x\!+\!1)\,(5)\!\!\!\! &&\qquad\quad\ \ \ 1 \,&=&\, \left<\color{#c00}{x^2+x+1},\ \color{#0a0}{x^3+x}\right> \end{eqnarray} ...

Newton's Method for Roots of Polynomials

https://math.stackexchange.com/q/742871

Congratulation, you have reinvented the Durand-Kerner method (1960) that was developed by Weierstraß in 1891. It has quite satisfying convergence, but may show a rather slow initial phase until the ...

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F=6x^{2}+3x+4x-1

Kombiner 5x^{2} og 1x^{2} for at få 6x^{2}.

F=6x^{2}+7x-1

Kombiner 3x og 4x for at få 7x.

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Lignende problemer fra websøgning

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