Løs 19leq03x+05x+02(60-x-y)leq20

$$19 \leq 03 x + 05 x + 02 ( 60 - x - y ) \leq 20$$

Evaluer

Løsningsvejledning

Multiplicer 0 og 3 for at få 0. Multiplicer 0 og 5 for at få 0. Multiplicer 0 og 2 for at få 0.

$$19\leq 0x+0x+0\left(60-x-y\right)\text{ and }0\times 3x+0\times 5x+0\times 2\left(60-x-y\right)\leq 20$$

Ethvert tal gange nul giver nul.

$$19\leq 0+0x+0\left(60-x-y\right)\text{ and }0\times 3x+0\times 5x+0\times 2\left(60-x-y\right)\leq 20$$

Ethvert tal gange nul giver nul.

$$19\leq 0+0+0\left(60-x-y\right)\text{ and }0\times 3x+0\times 5x+0\times 2\left(60-x-y\right)\leq 20$$

Tilføj 0 og 0 for at få 0.

$$19\leq 0\left(60-x-y\right)\text{ and }0\times 3x+0\times 5x+0\times 2\left(60-x-y\right)\leq 20$$

Ethvert tal gange nul giver nul.

$$19\leq 0\text{ and }0\times 3x+0\times 5x+0\times 2\left(60-x-y\right)\leq 20$$

Sammenlign 19 og 0.

$$\text{false}\text{ and }0\times 3x+0\times 5x+0\times 2\left(60-x-y\right)\leq 20$$

Multiplicer 0 og 3 for at få 0. Multiplicer 0 og 5 for at få 0. Multiplicer 0 og 2 for at få 0.

$$\text{false}\text{ and }0x+0x+0\left(60-x-y\right)\leq 20$$

Ethvert tal gange nul giver nul.

$$\text{false}\text{ and }0+0x+0\left(60-x-y\right)\leq 20$$

Ethvert tal gange nul giver nul.

$$\text{false}\text{ and }0+0+0\left(60-x-y\right)\leq 20$$

Tilføj 0 og 0 for at få 0.

$$\text{false}\text{ and }0\left(60-x-y\right)\leq 20$$

Ethvert tal gange nul giver nul.

$$\text{false}\text{ and }0\leq 20$$

Sammenlign 0 og 20.

$$\text{false}\text{ and }\text{true}$$

Foreningsmængden af \text{false} og \text{true} er \text{false}.

$$\text{false}$$