Løs -x^{3}y+2xy(-2/3x^2)+6x^2(-3/8xy)-y(-2x^3-1/4x^3)

$$- x ^ { 3 } y + 2 x y ( - \frac { 2 } { 3 } x ^ { 2 } ) + 6 x ^ { 2 } ( - \frac { 3 } { 8 } x y ) - y ( - 2 x ^ { 3 } - \frac { 1 } { 4 } x ^ { 3 } )$$

Evaluer

$$-\frac{7yx^{3}}{3}$$

Løsningsvejledning

Hvis du vil gange potenser for den samme base, skal du tilføje deres eksponenter. Tilføj 1 og 2 for at få 3.

$$\left(-x^{3}\right)y+2x^{3}y\left(-\frac{2}{3}\right)+6x^{2}\left(-\frac{3}{8}\right)xy-y\left(-2x^{3}-\frac{1}{4}x^{3}\right)$$

Hvis du vil gange potenser for den samme base, skal du tilføje deres eksponenter. Tilføj 2 og 1 for at få 3.

$$\left(-x^{3}\right)y+2x^{3}y\left(-\frac{2}{3}\right)+6x^{3}\left(-\frac{3}{8}\right)y-y\left(-2x^{3}-\frac{1}{4}x^{3}\right)$$

Multiplicer 2 og -\frac{2}{3} for at få -\frac{4}{3}.

$$\left(-x^{3}\right)y-\frac{4}{3}x^{3}y+6x^{3}\left(-\frac{3}{8}\right)y-y\left(-2x^{3}-\frac{1}{4}x^{3}\right)$$

Multiplicer 6 og -\frac{3}{8} for at få -\frac{9}{4}.

$$\left(-x^{3}\right)y-\frac{4}{3}x^{3}y-\frac{9}{4}x^{3}y-y\left(-2x^{3}-\frac{1}{4}x^{3}\right)$$

Kombiner -\frac{4}{3}x^{3}y og -\frac{9}{4}x^{3}y for at få -\frac{43}{12}x^{3}y.

$$\left(-x^{3}\right)y-\frac{43}{12}x^{3}y-y\left(-2x^{3}-\frac{1}{4}x^{3}\right)$$

Kombiner -2x^{3} og -\frac{1}{4}x^{3} for at få -\frac{9}{4}x^{3}.

$$\left(-x^{3}\right)y-\frac{43}{12}x^{3}y-y\left(-\frac{9}{4}\right)x^{3}$$

Kombiner -\frac{43}{12}x^{3}y og -y\left(-\frac{9}{4}\right)x^{3} for at få -\frac{4}{3}x^{3}y.

$$\left(-x^{3}\right)y-\frac{4}{3}x^{3}y$$

Kombiner -x^{3}y og -\frac{4}{3}x^{3}y for at få -\frac{7}{3}x^{3}y.

$$-\frac{7}{3}x^{3}y$$

Udvid

$$-\frac{7yx^{3}}{3}$$

Løsningsvejledning

Hvis du vil gange potenser for den samme base, skal du tilføje deres eksponenter. Tilføj 1 og 2 for at få 3.

$$\left(-x^{3}\right)y+2x^{3}y\left(-\frac{2}{3}\right)+6x^{2}\left(-\frac{3}{8}\right)xy-y\left(-2x^{3}-\frac{1}{4}x^{3}\right)$$

Hvis du vil gange potenser for den samme base, skal du tilføje deres eksponenter. Tilføj 2 og 1 for at få 3.

$$\left(-x^{3}\right)y+2x^{3}y\left(-\frac{2}{3}\right)+6x^{3}\left(-\frac{3}{8}\right)y-y\left(-2x^{3}-\frac{1}{4}x^{3}\right)$$

Multiplicer 2 og -\frac{2}{3} for at få -\frac{4}{3}.

$$\left(-x^{3}\right)y-\frac{4}{3}x^{3}y+6x^{3}\left(-\frac{3}{8}\right)y-y\left(-2x^{3}-\frac{1}{4}x^{3}\right)$$

Multiplicer 6 og -\frac{3}{8} for at få -\frac{9}{4}.

$$\left(-x^{3}\right)y-\frac{4}{3}x^{3}y-\frac{9}{4}x^{3}y-y\left(-2x^{3}-\frac{1}{4}x^{3}\right)$$

Kombiner -\frac{4}{3}x^{3}y og -\frac{9}{4}x^{3}y for at få -\frac{43}{12}x^{3}y.

$$\left(-x^{3}\right)y-\frac{43}{12}x^{3}y-y\left(-2x^{3}-\frac{1}{4}x^{3}\right)$$

Kombiner -2x^{3} og -\frac{1}{4}x^{3} for at få -\frac{9}{4}x^{3}.

$$\left(-x^{3}\right)y-\frac{43}{12}x^{3}y-y\left(-\frac{9}{4}\right)x^{3}$$

Kombiner -\frac{43}{12}x^{3}y og -y\left(-\frac{9}{4}\right)x^{3} for at få -\frac{4}{3}x^{3}y.

$$\left(-x^{3}\right)y-\frac{4}{3}x^{3}y$$

Kombiner -x^{3}y og -\frac{4}{3}x^{3}y for at få -\frac{7}{3}x^{3}y.

$$-\frac{7}{3}x^{3}y$$