Løs 1-sinTheta/cosθ=cosθ/1+sinθ

$$\frac { 1 - \sin \Theta } { \cos \theta } = \frac { \cos \theta } { 1 + \sin \theta }$$

Løs for Θ

$$\Theta =2\pi n_{2}-\theta +\pi \text{, }n_{2}\in \mathrm{Z}$$

$$\Theta =2\pi n_{3}+\theta \text{, }n_{3}\in \mathrm{Z}\text{, }\exists n_{1}\in \mathrm{Z}\text{ : }\left(\theta >\pi n_{1}+\frac{\pi }{2}\text{ and }\theta <\pi n_{1}+\frac{3\pi }{2}\right)$$

Løs for θ

$$\theta =2\pi n_{3}+\Theta \text{, }n_{3}\in \mathrm{Z}\text{, }\exists n_{1}\in \mathrm{Z}\text{ : }\left(\Theta >\pi n_{1}-2\pi n_{3}+\frac{\pi }{2}\text{ and }\Theta <\pi n_{1}-2\pi n_{3}+\frac{3\pi }{2}\right)$$

$$\theta =2\pi n_{2}-\Theta +\pi \text{, }n_{2}\in \mathrm{Z}\text{, }\exists n_{1}\in \mathrm{Z}\text{ : }\left(\Theta >2\pi n_{2}-\pi n_{1}-\frac{\pi }{2}\text{ and }\Theta <2\pi n_{2}-\pi n_{1}+\frac{\pi }{2}\right)$$