Neidio i'r prif gynnwys
Microsoft
|
Math Solver
Datrys
Ymarfer
Chwarae
Pynciau
Cyn-Algebra
Golygu
Modd
Ffactor Cyffredin Mwyaf
Lleiaf Cyffredin Lluosog
Urdd Gweithrediadau
Ffracsiynau
Ffracsiynau Cymysg
Prif Ffactorization
Dehonglwyr
Radicaliaid
Algebra
Cyfuno fel termau
Datrys ar gyfer Newidyn
Ffactor
Ehangu
Gwerthuso ffracsiynau
Hafaliadau llinol
Hafaliadau cwadratig
Anghydraddoldebau
Systemau Hafaliadau
Matricsau
Trigonometreg
Symleiddio
Gwerthuso
Graffiau
Datrys Hafaliadau
Calculus
Deilliadau
Integrynnau
Terfynau
Mewnbynnau algebra
Mewnbynnau trigonometreg
Mewnbynnau Calculus
Mewnbynnau Matrics
Datrys
Ymarfer
Chwarae
Pynciau
Cyn-Algebra
Golygu
Modd
Ffactor Cyffredin Mwyaf
Lleiaf Cyffredin Lluosog
Urdd Gweithrediadau
Ffracsiynau
Ffracsiynau Cymysg
Prif Ffactorization
Dehonglwyr
Radicaliaid
Algebra
Cyfuno fel termau
Datrys ar gyfer Newidyn
Ffactor
Ehangu
Gwerthuso ffracsiynau
Hafaliadau llinol
Hafaliadau cwadratig
Anghydraddoldebau
Systemau Hafaliadau
Matricsau
Trigonometreg
Symleiddio
Gwerthuso
Graffiau
Datrys Hafaliadau
Calculus
Deilliadau
Integrynnau
Terfynau
Mewnbynnau algebra
Mewnbynnau trigonometreg
Mewnbynnau Calculus
Mewnbynnau Matrics
Sylfaenol
algebra
trigonometreg
Calculus
ystadegau
matricsau
Cymeriadau
Enrhifo
0
Gwahaniaethu w.r.t. x
0
Cwis
Differentiation
5 problemau tebyg i:
\frac { d } { d x } ( 2 )
Problemau tebyg o chwiliad gwe
let f be a differentiable function. Compute \frac{d}{dx}g(2), where g(x) = \frac{f(2x)}{x}.
https://math.stackexchange.com/questions/2351494/let-f-be-a-differentiable-function-compute-fracddxg2-where-gx
You have an extra 4 in the numerator here: i know that : \dfrac{d}{dx}g(2)=\dfrac{4(\dfrac{d}{dx}f(4))-4f(4)}{4} If g(x) = \dfrac{f(2x)}x, then \begin{align*} \frac d{dx} g(x) &= \frac d{dx} ...
How to rewrite \frac{d}{d(x+c)}? [closed]
https://math.stackexchange.com/questions/1376627/how-to-rewrite-fracddxc
Use the chain rule. Define u = x + c then use the fact that \frac{d\cdot}{dx} = \frac{du}{dx} \frac{d\cdot}{du} where the \cdot represents any function, so \frac{df}{dx} = \frac{du}{dx} \frac{df}{du} ...
What does is the meaning of \frac{d}{dx}+x in (\frac{d}{dx}+x)y=0?
https://math.stackexchange.com/q/1590756
The symbols d/dx and x should both be interpreted as linear operators acting on a vector space that the unknown function y belongs to. The sum of linear operators is well-defined and that is ...
Intuitive explanation of \frac{\mathrm{d}}{\mathrm{d}x}=0?
https://math.stackexchange.com/questions/2894024/intuitive-explanation-of-frac-mathrmd-mathrmdx-0
Not sure about the problem but the strength of the electrical field, E, depends on your distance from it, which I assume is x. \frac{dE}{dx} then, is how much the strength of the field changes ...
Question about the chain rule.
https://math.stackexchange.com/q/2940216
Suppose we add an infinitesimal to x : x_1=x_0+\Delta x . What happens to y ? By definition, the derivative tells us how much a function changes relative to changes in its input: the change ...
Spectrum of the derivative operator
https://math.stackexchange.com/questions/2117107/spectrum-of-the-derivative-operator
\newcommand{\id}{I} As it was mentioned in the comments, the domain where you defined the operator is not correct - If you take C^1-functions with derivatives in L^2 the domain will be "too ...
Mwy Eitemau
Rhannu
Copi
Copïo i clipfwrdd
Problemau tebyg
\frac { d } { d x } ( 2 )
\frac { d } { d x } ( 4 x )
\frac { d } { d x } ( 6 x ^ 2 )
\frac { d } { d x } ( 3x+7 )
\frac { d } { d a } ( 6a ( a -2) )
\frac { d } { d z } ( \frac{z+3}{2z-4} )
Yn ôl i'r brig
