y^2-3y+18=(y-6)(y-4)-এর সমাধান করুন

$$y ^ { 2 } - 3 y + 18 = ( y - 6 ) ( y - 4 )$$

Solve for y

$$y=\frac{6}{7}\approx 0.857142857$$

Steps for Solving Linear Equation

Use the distributive property to multiply y-6 by y-4 and combine like terms.

$$y^{2}-3y+18=y^{2}-10y+24$$

Subtract y^{2} from both sides.

$$y^{2}-3y+18-y^{2}=-10y+24$$

Combine y^{2} and -y^{2} to get 0.

$$-3y+18=-10y+24$$

Add 10y to both sides.

$$-3y+18+10y=24$$

Combine -3y and 10y to get 7y.

$$7y+18=24$$

Subtract 18 from both sides.

$$7y=24-18$$

Subtract 18 from 24 to get 6.

$$7y=6$$

Divide both sides by 7.

$$y=\frac{6}{7}$$