m^2(x-2)leq4(x+m)-এর সমাধান করুন

$$m ^ { 2 } ( x - 2 ) \leq 4 ( x + m )$$

x এর জন্য সমাধান করুন

$$\left\{\begin{matrix}x\leq \frac{2m}{m-2}\text{, }&|m|\geq 2\text{ and }m\neq 2\\x\geq \frac{2m}{m-2}\text{, }&m\neq 2\text{ and }|m|\leq 2\\x\in \mathrm{R}\text{, }&|m|=2\\x=\frac{2m}{m-2}\text{, }&m\neq 2\end{matrix}\right.$$

m এর জন্য সমাধান করুন

$$\left\{\begin{matrix}m\in (-\infty,\frac{2(|x-1|+1)}{x-2}]\cup [-\frac{2(|x-1|-1)}{x-2},\infty)\text{, }&x<2\\m\in [-\frac{2(|x-1|-1)}{x-2},\frac{2(|x-1|+1)}{x-2}]\text{, }&x=1\text{ or }x>2\\m\in [-2,\frac{2(|x-1|+1)}{x-2}]\text{, }&x>2\text{ or }x\leq 1\\m=\frac{2x}{x-2}\text{, }&x=1\\m\geq -2\text{, }&x\geq 1\text{ and }x\leq 2\end{matrix}\right.$$