AB+BC=AC-এর সমাধান করুন

$$A B + B C = A C$$

Solve for A

$$\left\{\begin{matrix}A=-\frac{BC}{B-C}\text{, }&B\neq C\\A\in \mathrm{R}\text{, }&C=0\text{ and }B=0\end{matrix}\right.$$

Steps for Solving Linear Equation

Subtract AC from both sides.

$$AB+BC-AC=0$$

Subtract BC from both sides. Anything subtracted from zero gives its negation.

$$AB-AC=-BC$$

Combine all terms containing A.

$$\left(B-C\right)A=-BC$$

Divide both sides by B-C.

$$\frac{\left(B-C\right)A}{B-C}=-\frac{BC}{B-C}$$

Dividing by B-C undoes the multiplication by B-C.

$$A=-\frac{BC}{B-C}$$

Solve for B

$$\left\{\begin{matrix}B=\frac{AC}{A+C}\text{, }&A\neq -C\\B\in \mathrm{R}\text{, }&C=0\text{ and }A=0\end{matrix}\right.$$

Steps for Solving Linear Equation

Combine all terms containing B.

$$\left(A+C\right)B=AC$$

Divide both sides by A+C.

$$\frac{\left(A+C\right)B}{A+C}=\frac{AC}{A+C}$$

Dividing by A+C undoes the multiplication by A+C.

$$B=\frac{AC}{A+C}$$