9-2(x+4)-10(25-x+4)=5-3x-4(x+1)-এর সমাধান করুন

$$9-2(x+4)-10(25-x+4)=5-3x-4(x+1)$$

Solve for x

$$x = \frac{58}{3} = 19\frac{1}{3} \approx 19.333333333$$

Steps for Solving Linear Equation

Use the distributive property to multiply -2 by x+4.

$$9-2x-8-10\left(25-x+4\right)=5-3x-4\left(x+1\right)$$

Subtract 8 from 9 to get 1.

$$1-2x-10\left(25-x+4\right)=5-3x-4\left(x+1\right)$$

Add 25 and 4 to get 29.

$$1-2x-10\left(29-x\right)=5-3x-4\left(x+1\right)$$

Use the distributive property to multiply -10 by 29-x.

$$1-2x-290+10x=5-3x-4\left(x+1\right)$$

Subtract 290 from 1 to get -289.

$$-289-2x+10x=5-3x-4\left(x+1\right)$$

Combine -2x and 10x to get 8x.

$$-289+8x=5-3x-4\left(x+1\right)$$

Use the distributive property to multiply -4 by x+1.

$$-289+8x=5-3x-4x-4$$

Combine -3x and -4x to get -7x.

$$-289+8x=5-7x-4$$

Subtract 4 from 5 to get 1.

$$-289+8x=1-7x$$

Add 7x to both sides.

$$-289+8x+7x=1$$

Combine 8x and 7x to get 15x.

$$-289+15x=1$$

Add 289 to both sides.

$$15x=1+289$$

Add 1 and 289 to get 290.

$$15x=290$$

Divide both sides by 15.

$$x=\frac{290}{15}$$

Reduce the fraction \frac{290}{15} to lowest terms by extracting and canceling out 5.

$$x=\frac{58}{3}$$