5-left(x-4right)^2-এর সমাধান করুন

$$5- { \left(x-4 \right) }^{ 2 }$$

Evaluate

$$-\left(x-4\right)^{2}+5$$

Solution Steps

Use binomial theorem \left(a-b\right)^{2}=a^{2}-2ab+b^{2} to expand \left(x-4\right)^{2}.

$$5-\left(x^{2}-8x+16\right)$$

To find the opposite of x^{2}-8x+16, find the opposite of each term.

$$5-x^{2}+8x-16$$

Subtract 16 from 5 to get -11.

$$-11-x^{2}+8x$$

Expand

$$-x^{2}+8x-11$$

Solution Steps

Use binomial theorem \left(a-b\right)^{2}=a^{2}-2ab+b^{2} to expand \left(x-4\right)^{2}.

$$5-\left(x^{2}-8x+16\right)$$

To find the opposite of x^{2}-8x+16, find the opposite of each term.

$$5-x^{2}+8x-16$$

Subtract 16 from 5 to get -11.

$$-11-x^{2}+8x$$