4m^2-2m-(2m-1)^2-এর সমাধান করুন

$$4 m ^ { 2 } - 2 m - ( 2 m - 1 ) ^ { 2 }$$

Evaluate

$$2m-1$$

Solution Steps

Use binomial theorem \left(a-b\right)^{2}=a^{2}-2ab+b^{2} to expand \left(2m-1\right)^{2}.

$$4m^{2}-2m-\left(4m^{2}-4m+1\right)$$

To find the opposite of 4m^{2}-4m+1, find the opposite of each term.

$$4m^{2}-2m-4m^{2}+4m-1$$

Combine 4m^{2} and -4m^{2} to get 0.

$$-2m+4m-1$$

Combine -2m and 4m to get 2m.

$$2m-1$$

Expand

$$2m-1$$

Solution Steps

Use binomial theorem \left(a-b\right)^{2}=a^{2}-2ab+b^{2} to expand \left(2m-1\right)^{2}.

$$4m^{2}-2m-\left(4m^{2}-4m+1\right)$$

To find the opposite of 4m^{2}-4m+1, find the opposite of each term.

$$4m^{2}-2m-4m^{2}+4m-1$$

Combine 4m^{2} and -4m^{2} to get 0.

$$-2m+4m-1$$

Combine -2m and 4m to get 2m.

$$2m-1$$