3(3y+1)<13y-8-এর সমাধান করুন

$$3 ( 3 y + 1 ) < 13 y - 8$$

Solve for y

$$y>\frac{11}{4}$$

Solution Steps

Use the distributive property to multiply 3 by 3y+1.

$$9y+3<13y-8$$

Subtract 13y from both sides.

$$9y+3-13y<-8$$

Combine 9y and -13y to get -4y.

$$-4y+3<-8$$

Subtract 3 from both sides.

$$-4y<-8-3$$

Subtract 3 from -8 to get -11.

$$-4y<-11$$

Divide both sides by -4. Since -4 is negative, the inequality direction is changed.

$$y>\frac{-11}{-4}$$

Fraction \frac{-11}{-4} can be simplified to \frac{11}{4} by removing the negative sign from both the numerator and the denominator.

$$y>\frac{11}{4}$$