21m^{3}n^{2}+3mn^2-6mn^3+9m^2n^2=-এর সমাধান করুন

$$21 m ^ { 3 } n ^ { 2 } + 3 mn ^ { 2 } - 6 mn ^ { 3 } + 9 m ^ { 2 } n ^ { 2 } =$$

Factor

$$3mn^{2}\left(7m^{2}+3m-2n+1\right)$$

Solution Steps

Factor out 3.

$$3\left(7m^{3}n^{2}+mn^{2}-2mn^{3}+3m^{2}n^{2}\right)$$

Consider 7m^{3}n^{2}+mn^{2}-2mn^{3}+3m^{2}n^{2}. Factor out mn^{2}.

$$mn^{2}\left(7m^{2}+1-2n+3m\right)$$

Rewrite the complete factored expression.

$$3mn^{2}\left(7m^{2}+1-2n+3m\right)$$

Evaluate

$$3mn^{2}\left(7m^{2}+3m-2n+1\right)$$