2y*8u^7*2y^2u^8-এর সমাধান করুন

$$2 y \cdot 8 u ^ { 7 } \cdot 2 y ^ { 2 } u ^ { 8 }$$

Evaluate

$$32y^{3}u^{15}$$

Solution Steps

To multiply powers of the same base, add their exponents. Add 1 and 2 to get 3.

$$2y^{3}\times 8u^{7}\times 2u^{8}$$

To multiply powers of the same base, add their exponents. Add 7 and 8 to get 15.

$$2y^{3}\times 8u^{15}\times 2$$

Multiply 2 and 8 to get 16.

$$16y^{3}u^{15}\times 2$$

Multiply 16 and 2 to get 32.

$$32y^{3}u^{15}$$

Differentiate w.r.t. y

$$96y^{2}u^{15}$$