2(-99+68a)>3(-6+52a)-এর সমাধান করুন

$$2 ( - 99 + 68 a ) > 3 ( - 6 + 52 a )$$

Solve for a

$$a<-9$$

Solution Steps

Use the distributive property to multiply 2 by -99+68a.

$$-198+136a>3\left(-6+52a\right)$$

Use the distributive property to multiply 3 by -6+52a.

$$-198+136a>-18+156a$$

Subtract 156a from both sides.

$$-198+136a-156a>-18$$

Combine 136a and -156a to get -20a.

$$-198-20a>-18$$

Add 198 to both sides.

$$-20a>-18+198$$

Add -18 and 198 to get 180.

$$-20a>180$$

Divide both sides by -20. Since -20 is negative, the inequality direction is changed.

$$a<\frac{180}{-20}$$

Divide 180 by -20 to get -9.

$$a<-9$$