Solve for x
x = \frac{20}{3} = 6\frac{2}{3} \approx 6.666666667
x=20
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12x^{2}-320x+1600=0
All equations of the form ax^{2}+bx+c=0 can be solved using the quadratic formula: \frac{-b±\sqrt{b^{2}-4ac}}{2a}. The quadratic formula gives two solutions, one when ± is addition and one when it is subtraction.
x=\frac{-\left(-320\right)±\sqrt{\left(-320\right)^{2}-4\times 12\times 1600}}{2\times 12}
This equation is in standard form: ax^{2}+bx+c=0. Substitute 12 for a, -320 for b, and 1600 for c in the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.
x=\frac{-\left(-320\right)±\sqrt{102400-4\times 12\times 1600}}{2\times 12}
Square -320.
x=\frac{-\left(-320\right)±\sqrt{102400-48\times 1600}}{2\times 12}
Multiply -4 times 12.
x=\frac{-\left(-320\right)±\sqrt{102400-76800}}{2\times 12}
Multiply -48 times 1600.
x=\frac{-\left(-320\right)±\sqrt{25600}}{2\times 12}
Add 102400 to -76800.
x=\frac{-\left(-320\right)±160}{2\times 12}
Take the square root of 25600.
x=\frac{320±160}{2\times 12}
The opposite of -320 is 320.
x=\frac{320±160}{24}
Multiply 2 times 12.
x=\frac{480}{24}
Now solve the equation x=\frac{320±160}{24} when ± is plus. Add 320 to 160.
x=20
Divide 480 by 24.
x=\frac{160}{24}
Now solve the equation x=\frac{320±160}{24} when ± is minus. Subtract 160 from 320.
x=\frac{20}{3}
Reduce the fraction \frac{160}{24} to lowest terms by extracting and canceling out 8.
x=20 x=\frac{20}{3}
The equation is now solved.
12x^{2}-320x+1600=0
Quadratic equations such as this one can be solved by completing the square. In order to complete the square, the equation must first be in the form x^{2}+bx=c.
12x^{2}-320x+1600-1600=-1600
Subtract 1600 from both sides of the equation.
12x^{2}-320x=-1600
Subtracting 1600 from itself leaves 0.
\frac{12x^{2}-320x}{12}=-\frac{1600}{12}
Divide both sides by 12.
x^{2}+\left(-\frac{320}{12}\right)x=-\frac{1600}{12}
Dividing by 12 undoes the multiplication by 12.
x^{2}-\frac{80}{3}x=-\frac{1600}{12}
Reduce the fraction \frac{-320}{12} to lowest terms by extracting and canceling out 4.
x^{2}-\frac{80}{3}x=-\frac{400}{3}
Reduce the fraction \frac{-1600}{12} to lowest terms by extracting and canceling out 4.
x^{2}-\frac{80}{3}x+\left(-\frac{40}{3}\right)^{2}=-\frac{400}{3}+\left(-\frac{40}{3}\right)^{2}
Divide -\frac{80}{3}, the coefficient of the x term, by 2 to get -\frac{40}{3}. Then add the square of -\frac{40}{3} to both sides of the equation. This step makes the left hand side of the equation a perfect square.
x^{2}-\frac{80}{3}x+\frac{1600}{9}=-\frac{400}{3}+\frac{1600}{9}
Square -\frac{40}{3} by squaring both the numerator and the denominator of the fraction.
x^{2}-\frac{80}{3}x+\frac{1600}{9}=\frac{400}{9}
Add -\frac{400}{3} to \frac{1600}{9} by finding a common denominator and adding the numerators. Then reduce the fraction to lowest terms if possible.
\left(x-\frac{40}{3}\right)^{2}=\frac{400}{9}
Factor x^{2}-\frac{80}{3}x+\frac{1600}{9}. In general, when x^{2}+bx+c is a perfect square, it can always be factored as \left(x+\frac{b}{2}\right)^{2}.
\sqrt{\left(x-\frac{40}{3}\right)^{2}}=\sqrt{\frac{400}{9}}
Take the square root of both sides of the equation.
x-\frac{40}{3}=\frac{20}{3} x-\frac{40}{3}=-\frac{20}{3}
Simplify.
x=20 x=\frac{20}{3}
Add \frac{40}{3} to both sides of the equation.
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