-4z+1=bz+c-এর সমাধান করুন

$$- 4 z + 1 = b z + c$$

Solve for b

$$\left\{\begin{matrix}b=-\frac{4z+c-1}{z}\text{, }&z\neq 0\\b\in \mathrm{R}\text{, }&z=0\text{ and }c=1\end{matrix}\right.$$

Steps for Solving Linear Equation

Swap sides so that all variable terms are on the left hand side.

$$bz+c=-4z+1$$

Subtract c from both sides.

$$bz=-4z+1-c$$

The equation is in standard form.

$$zb=1-c-4z$$

Divide both sides by z.

$$\frac{zb}{z}=\frac{1-c-4z}{z}$$

Dividing by z undoes the multiplication by z.

$$b=\frac{1-c-4z}{z}$$

Solve for c

$$c=1-4z-bz$$

Solution Steps

Swap sides so that all variable terms are on the left hand side.

$$bz+c=-4z+1$$

Subtract bz from both sides.

$$c=-4z+1-bz$$