{l}{cos(θ)=-3/4}{a=cos(2θ)}{b=a}{text{Solvefor}ctext{where}}{c=b}-এর সমাধান করুন

$$\left. \begin{array} { l } { \cos(\theta) = -\frac{3}{4} }\\ { a = \cos(2 \theta) }\\ { b = a }\\ { \text{Solve for } c \text{ where} } \\ { c = b } \end{array} \right.$$

θ, a, b, c এর জন্য সমাধান করুন

$$\theta =2\pi n_{1}+\pi -\arccos(\frac{3}{4})\text{, }n_{1}\in \mathrm{Z}\text{, }a=\frac{1}{8}=0.125\text{, }b=\frac{1}{8}=0.125\text{, }c=\frac{1}{8}=0.125$$

$$\theta =2\pi n_{2}+\pi +\arccos(\frac{3}{4})\text{, }n_{2}\in \mathrm{Z}\text{, }a=\frac{1}{8}=0.125\text{, }b=\frac{1}{8}=0.125\text{, }c=\frac{1}{8}=0.125$$