∫ (from 0 to 1) of sqrt{1-z^2}-এর সমাধান করুন

$$\int _ { 0 } ^ { 1 } \sqrt { 1 - z ^ { 2 } }$$

মূল্যায়ন করুন

$$\sqrt{1-z^{2}}$$

সমাধানের ধাপগুলো

Evaluate the indefinite integral first.

$$\int \sqrt{1-z^{2}}\mathrm{d}x$$

Find the integral of \sqrt{1-z^{2}} using the table of common integrals rule \int a\mathrm{d}x=ax.

$$\sqrt{1-z^{2}}x$$

The definite integral is the antiderivative of the expression evaluated at the upper limit of integration minus the antiderivative evaluated at the lower limit of integration.

$$\left(1-z^{2}\right)^{\frac{1}{2}}\times 1-\left(1-z^{2}\right)^{\frac{1}{2}}\times 0$$

সিমপ্লিফাই।

$$\sqrt{1-z^{2}}$$

w.r.t. z পার্থক্য করুন

$$-\frac{z}{\sqrt{1-z^{2}}}$$