∫ 9x^3+2 wrt x-এর সমাধান করুন

$$\int 9 x ^ { 3 } + 2 d x$$

মূল্যায়ন করুন

$$\frac{9x^{4}}{4}+2x+С$$

সমাধানের ধাপগুলো

Integrate the sum term by term.

$$\int 9x^{3}\mathrm{d}x+\int 2\mathrm{d}x$$

Factor out the constant in each of the terms.

$$9\int x^{3}\mathrm{d}x+\int 2\mathrm{d}x$$

Since \int x^{k}\mathrm{d}x=\frac{x^{k+1}}{k+1} for k\neq -1, replace \int x^{3}\mathrm{d}x with \frac{x^{4}}{4}. 9 কে \frac{x^{4}}{4} বার গুণ করুন।

$$\frac{9x^{4}}{4}+\int 2\mathrm{d}x$$

Find the integral of 2 using the table of common integrals rule \int a\mathrm{d}x=ax.

$$\frac{9x^{4}}{4}+2x$$

If F\left(x\right) is an antiderivative of f\left(x\right), then the set of all antiderivatives of f\left(x\right) is given by F\left(x\right)+C. Therefore, add the constant of integration C\in \mathrm{R} to the result.

$$\frac{9x^{4}}{4}+2x+С$$

w.r.t. x পার্থক্য করুন

$$9x^{3}+2$$