∫ 5x wrt x-এর সমাধান করুন

$$\int 5 x d x$$

মূল্যায়ন করুন

$$\frac{5x^{2}}{2}+С$$

সমাধানের ধাপগুলো

Factor out the constant using \int af\left(x\right)\mathrm{d}x=a\int f\left(x\right)\mathrm{d}x.

$$5\int x\mathrm{d}x$$

Since \int x^{k}\mathrm{d}x=\frac{x^{k+1}}{k+1} for k\neq -1, replace \int x\mathrm{d}x with \frac{x^{2}}{2}.

$$\frac{5x^{2}}{2}$$

If F\left(x\right) is an antiderivative of f\left(x\right), then the set of all antiderivatives of f\left(x\right) is given by F\left(x\right)+C. Therefore, add the constant of integration C\in \mathrm{R} to the result.

$$\frac{5x^{2}}{2}+С$$

w.r.t. x পার্থক্য করুন

$$5x$$