∫ (x^2-3x) wrt x-এর সমাধান করুন

$$\int ( x ^ { 2 } - 3 x ) d x$$

মূল্যায়ন করুন

$$\frac{x^{3}}{3}-\frac{3x^{2}}{2}+С$$

সমাধানের ধাপগুলো

Integrate the sum term by term.

$$\int x^{2}\mathrm{d}x+\int -3x\mathrm{d}x$$

Factor out the constant in each of the terms.

$$\int x^{2}\mathrm{d}x-3\int x\mathrm{d}x$$

Since \int x^{k}\mathrm{d}x=\frac{x^{k+1}}{k+1} for k\neq -1, replace \int x^{2}\mathrm{d}x with \frac{x^{3}}{3}.

$$\frac{x^{3}}{3}-3\int x\mathrm{d}x$$

Since \int x^{k}\mathrm{d}x=\frac{x^{k+1}}{k+1} for k\neq -1, replace \int x\mathrm{d}x with \frac{x^{2}}{2}. -3 কে \frac{x^{2}}{2} বার গুণ করুন।

$$\frac{x^{3}}{3}-\frac{3x^{2}}{2}$$

If F\left(x\right) is an antiderivative of f\left(x\right), then the set of all antiderivatives of f\left(x\right) is given by F\left(x\right)+C. Therefore, add the constant of integration C\in \mathrm{R} to the result.

$$\frac{x^{3}}{3}-\frac{3x^{2}}{2}+С$$

w.r.t. x পার্থক্য করুন

$$x\left(x-3\right)$$