∫ (-2)+int(0.2)-এর সমাধান করুন

$$\int ( - 2 ) + \int ( 0.2 )$$

মূল্যায়ন করুন

$$Сx+\frac{x^{2}}{10}+С_{1}$$

সমাধানের ধাপগুলো

Integrate the sum term by term.

$$\int -2\mathrm{d}x+\int \int 0.2\mathrm{d}x\mathrm{d}x$$

Find the integral of -2 using the table of common integrals rule \int a\mathrm{d}x=ax.

$$-2x+\int \int 0.2\mathrm{d}x\mathrm{d}x$$

সিমপ্লিফাই।

$$-2x+\frac{x^{2}}{10}+Сx$$

If F\left(x\right) is an antiderivative of f\left(x\right), then the set of all antiderivatives of f\left(x\right) is given by F\left(x\right)+C. Therefore, add the constant of integration C\in \mathrm{R} to the result.

$$-2x+\frac{x^{2}}{10}+Сx+С$$

w.r.t. x পার্থক্য করুন

$$\frac{x}{5}+С$$