∫ (sqrt{x}+sqrt[3]{x^4}+3sqrt{x^3}) wrt x-এর সমাধান করুন

$$\int ( \sqrt { x } + \sqrt[ 3 ] { x ^ { 4 } } + 3 \sqrt { x ^ { 3 } } ) d x$$

মূল্যায়ন করুন

$$\frac{6x^{\frac{5}{2}}}{5}+\frac{3x^{\frac{7}{3}}}{7}+\frac{2x^{\frac{3}{2}}}{3}+С$$

সমাধানের ধাপগুলো

Integrate the sum term by term.

$$\int \sqrt{x}\mathrm{d}x+\int x^{\frac{4}{3}}\mathrm{d}x+\int 3x^{\frac{3}{2}}\mathrm{d}x$$

Factor out the constant in each of the terms.

$$\int \sqrt{x}\mathrm{d}x+\int x^{\frac{4}{3}}\mathrm{d}x+3\int x^{\frac{3}{2}}\mathrm{d}x$$

x^{\frac{1}{2}} হিসেবে \sqrt{x} পুনরায় লিখুন৷ Since \int x^{k}\mathrm{d}x=\frac{x^{k+1}}{k+1} for k\neq -1, replace \int x^{\frac{1}{2}}\mathrm{d}x with \frac{x^{\frac{3}{2}}}{\frac{3}{2}}. সিমপ্লিফাই।

$$\frac{2x^{\frac{3}{2}}}{3}+\int x^{\frac{4}{3}}\mathrm{d}x+3\int x^{\frac{3}{2}}\mathrm{d}x$$

Since \int x^{k}\mathrm{d}x=\frac{x^{k+1}}{k+1} for k\neq -1, replace \int x^{\frac{4}{3}}\mathrm{d}x with \frac{3x^{\frac{7}{3}}}{7}.

$$\frac{2x^{\frac{3}{2}}}{3}+\frac{3x^{\frac{7}{3}}}{7}+3\int x^{\frac{3}{2}}\mathrm{d}x$$

Since \int x^{k}\mathrm{d}x=\frac{x^{k+1}}{k+1} for k\neq -1, replace \int x^{\frac{3}{2}}\mathrm{d}x with \frac{2x^{\frac{5}{2}}}{5}. 3 কে \frac{2x^{\frac{5}{2}}}{5} বার গুণ করুন।

$$\frac{2x^{\frac{3}{2}}}{3}+\frac{3x^{\frac{7}{3}}}{7}+\frac{6x^{\frac{5}{2}}}{5}$$

If F\left(x\right) is an antiderivative of f\left(x\right), then the set of all antiderivatives of f\left(x\right) is given by F\left(x\right)+C. Therefore, add the constant of integration C\in \mathrm{R} to the result.

$$\frac{2x^{\frac{3}{2}}}{3}+\frac{3x^{\frac{7}{3}}}{7}+\frac{6x^{\frac{5}{2}}}{5}+С$$

w.r.t. x পার্থক্য করুন

$$\sqrt{x}\left(3x+x^{\frac{5}{6}}+1\right)$$