∫ (2/x^2+x+1) wrt x-এর সমাধান করুন

$$\int ( \frac { 2 } { x ^ { 2 } } + x + 1 ) d x$$

মূল্যায়ন করুন

$$\frac{x^{2}}{2}+x-\frac{2}{x}+С$$

সমাধানের ধাপগুলো

Integrate the sum term by term.

$$\int \frac{2}{x^{2}}\mathrm{d}x+\int x\mathrm{d}x+\int 1\mathrm{d}x$$

Factor out the constant in each of the terms.

$$2\int \frac{1}{x^{2}}\mathrm{d}x+\int x\mathrm{d}x+\int 1\mathrm{d}x$$

Since \int x^{k}\mathrm{d}x=\frac{x^{k+1}}{k+1} for k\neq -1, replace \int \frac{1}{x^{2}}\mathrm{d}x with -\frac{1}{x}. 2 কে -\frac{1}{x} বার গুণ করুন।

$$-\frac{2}{x}+\int x\mathrm{d}x+\int 1\mathrm{d}x$$

Since \int x^{k}\mathrm{d}x=\frac{x^{k+1}}{k+1} for k\neq -1, replace \int x\mathrm{d}x with \frac{x^{2}}{2}.

$$-\frac{2}{x}+\frac{x^{2}}{2}+\int 1\mathrm{d}x$$

Find the integral of 1 using the table of common integrals rule \int a\mathrm{d}x=ax.

$$-\frac{2}{x}+\frac{x^{2}}{2}+x$$

If F\left(x\right) is an antiderivative of f\left(x\right), then the set of all antiderivatives of f\left(x\right) is given by F\left(x\right)+C. Therefore, add the constant of integration C\in \mathrm{R} to the result.

$$-\frac{2}{x}+\frac{x^{2}}{2}+x+С$$

w.r.t. x পার্থক্য করুন

$$x+1+\frac{2}{x^{2}}$$