∫ 5/x^3 wrt x-এর সমাধান করুন

$$\int \frac { 5 } { x ^ { 3 } } d x$$

মূল্যায়ন করুন

$$-\frac{5}{2x^{2}}+С$$

সমাধানের ধাপগুলো

Factor out the constant using \int af\left(x\right)\mathrm{d}x=a\int f\left(x\right)\mathrm{d}x.

$$5\int \frac{1}{x^{3}}\mathrm{d}x$$

Since \int x^{k}\mathrm{d}x=\frac{x^{k+1}}{k+1} for k\neq -1, replace \int \frac{1}{x^{3}}\mathrm{d}x with -\frac{1}{2x^{2}}.

$$-\frac{\frac{5}{x^{2}}}{2}$$

সিমপ্লিফাই।

$$-\frac{5}{2x^{2}}$$

If F\left(x\right) is an antiderivative of f\left(x\right), then the set of all antiderivatives of f\left(x\right) is given by F\left(x\right)+C. Therefore, add the constant of integration C\in \mathrm{R} to the result.

$$-\frac{5}{2x^{2}}+С$$

w.r.t. x পার্থক্য করুন

$$\frac{5}{x^{3}}$$