∫ 1/2sqrt{x}-এর সমাধান করুন

$$\int \frac { 1 } { 2 \sqrt { x } }$$

মূল্যায়ন করুন

$$\sqrt{x}+С$$

সমাধানের ধাপগুলো

Factor out the constant using \int af\left(x\right)\mathrm{d}x=a\int f\left(x\right)\mathrm{d}x.

$$\frac{\int \frac{1}{\sqrt{x}}\mathrm{d}x}{2}$$

x^{-\frac{1}{2}} হিসেবে \frac{1}{\sqrt{x}} পুনরায় লিখুন৷ Since \int x^{k}\mathrm{d}x=\frac{x^{k+1}}{k+1} for k\neq -1, replace \int x^{-\frac{1}{2}}\mathrm{d}x with \frac{x^{\frac{1}{2}}}{\frac{1}{2}}. Simplify and convert from exponential to radical form.

$$\sqrt{x}$$

If F\left(x\right) is an antiderivative of f\left(x\right), then the set of all antiderivatives of f\left(x\right) is given by F\left(x\right)+C. Therefore, add the constant of integration C\in \mathrm{R} to the result.

$$\sqrt{x}+С$$

w.r.t. x পার্থক্য করুন

$$\frac{1}{2\sqrt{x}}$$