4^2+6(4)-27/4^2-8(4)+7-এর সমাধান করুন

$$\frac { 4 ^ { 2 } + 6 ( 4 ) - 27 } { 4 ^ { 2 } - 8 ( 4 ) + 7 }$$

Evaluate

$$-\frac{13}{9}\approx -1.444444444$$

Solution Steps

Calculate 4 to the power of 2 and get 16.

$$\frac{16+6\times 4-27}{4^{2}-8\times 4+7}$$

Multiply 6 and 4 to get 24.

$$\frac{16+24-27}{4^{2}-8\times 4+7}$$

Add 16 and 24 to get 40.

$$\frac{40-27}{4^{2}-8\times 4+7}$$

Subtract 27 from 40 to get 13.

$$\frac{13}{4^{2}-8\times 4+7}$$

Calculate 4 to the power of 2 and get 16.

$$\frac{13}{16-8\times 4+7}$$

Multiply 8 and 4 to get 32.

$$\frac{13}{16-32+7}$$

Subtract 32 from 16 to get -16.

$$\frac{13}{-16+7}$$

Add -16 and 7 to get -9.

$$\frac{13}{-9}$$

Fraction \frac{13}{-9} can be rewritten as -\frac{13}{9} by extracting the negative sign.

$$-\frac{13}{9}$$

Factor

$$-\frac{13}{9} = -1\frac{4}{9} \approx -1.444444444$$