$\fraction{2}{3} - 5 x = b x + \fraction{1}{3} $
Solve for b
b=-5+\frac{1}{3x},x\neq 0
Solve for x
x=\frac{1}{3\left(b+5\right)},b\neq -5
গ্রাফ
শেয়ার করুন
ক্লিপবোর্ডে কপি করা হয়েছে
bx+\frac{1}{3}=\frac{2}{3}-5x
Swap sides so that all variable terms are on the left hand side.
bx=\frac{2}{3}-5x-\frac{1}{3}
Subtract \frac{1}{3} from both sides.
bx=\frac{1}{3}-5x
Subtract \frac{1}{3} from \frac{2}{3} to get \frac{1}{3}.
xb=\frac{1}{3}-5x
The equation is in standard form.
\frac{xb}{x}=\frac{\frac{1}{3}-5x}{x}
Divide both sides by x.
b=\frac{\frac{1}{3}-5x}{x}
Dividing by x undoes the multiplication by x.
b=-5+\frac{1}{3x}
Divide \frac{1}{3}-5x by x.
\frac{2}{3}-5x-bx=\frac{1}{3}
Subtract bx from both sides.
-5x-bx=\frac{1}{3}-\frac{2}{3}
Subtract \frac{2}{3} from both sides.
-5x-bx=-\frac{1}{3}
Subtract \frac{2}{3} from \frac{1}{3} to get -\frac{1}{3}.
\left(-5-b\right)x=-\frac{1}{3}
Combine all terms containing x.
\left(-b-5\right)x=-\frac{1}{3}
The equation is in standard form.
\frac{\left(-b-5\right)x}{-b-5}=\frac{-\frac{1}{3}}{-b-5}
Divide both sides by -5-b.
x=\frac{-\frac{1}{3}}{-b-5}
Dividing by -5-b undoes the multiplication by -5-b.
x=\frac{1}{3\left(b+5\right)}
Divide -\frac{1}{3} by -5-b.
উদাহরণ
দ্বিঘাত সমীকরণ
{ x } ^ { 2 } - 4 x - 5 = 0
ত্রিকোণমিতি
4 \sin \theta \cos \theta = 2 \sin \theta
রৈখিক সমীকরণ
y = 3x + 4
পাটিগণিত
699 * 533
মেট্রিক্স
\left[ \begin{array} { l l } { 2 } & { 3 } \\ { 5 } & { 4 } \end{array} \right] \left[ \begin{array} { l l l } { 2 } & { 0 } & { 3 } \\ { -1 } & { 1 } & { 5 } \end{array} \right]
সমকালীন সমীকরণ
\left. \begin{cases} { 8x+2y = 46 } \\ { 7x+3y = 47 } \end{cases} \right.
ডিফারেন্সিয়েশন
\frac { d } { d x } \frac { ( 3 x ^ { 2 } - 2 ) } { ( x - 5 ) }
ইন্টিগ্রেশন
\int _ { 0 } ^ { 1 } x e ^ { - x ^ { 2 } } d x
লিমিট
\lim _{x \rightarrow-3} \frac{x^{2}-9}{x^{2}+2 x-3}