Solve 2x^2geq50

$$2x^2 \geq 50$$

Solve for x

$$x\in (-\infty,-5]\cup [5,\infty)$$

Solution Steps

Divide both sides by 2. Since 2 is positive, the inequality direction remains the same.

$$x^{2}\geq \frac{50}{2}$$

Divide 50 by 2 to get 25.

$$x^{2}\geq 25$$

Calculate the square root of 25 and get 5. Rewrite 25 as 5^{2}.

$$x^{2}\geq 5^{2}$$

Inequality holds for |x|\geq 5.

$$|x|\geq 5$$

Rewrite |x|\geq 5 as x\leq -5\text{; }x\geq 5.

$$x\leq -5\text{; }x\geq 5$$