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4
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4%20%60frac%7B%2015%20%20%7D%7B%2032%20%20%7D%20
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4
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2^{2}
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5 道与此类似的题目:
4%20%60frac%7B%2015%20%20%7D%7B%2032%20%20%7D%20
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sum of all coprimes of a number.
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Yes, the formula is right and if you reached it by yourself it is remarkable. If \;\phi(n)\; is Euler's Totient Function, then the sum you want is \frac n2\phi(n)=\frac{n^2}2\prod_{p\mid n\,,\,p\,\text{a prime}}\left(1-\frac1p\right) ...
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Let f(n) be the expected final win for a player already having a balance of n and employing the optimal strategy. Trivially, f(n)\ge n as he might decide to stop right now. However, if the ...
P(A \cap B) = \frac14, P(\neg A) = \frac13, P(B) = \frac12, P(A \cup B) =?
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The solution for this would be Risk Neutral Probability = \frac{(1-d-(1+r)k)}{u-d-(1+r)k} Fair Price of the Option = \frac{1}{1+r}\left(p\psi{(u)}+(1-p)\psi{(d)}\right) where \psi{(u)} = Max((110-100),0) = 10 ...
Prove that \frac{1}{a(a-b)(a-c)} +\frac{1}{b(b-c)(b-a)} +\frac{1}{c(c-a)(c-b)} =\frac{1}{abc} for all sets of distinct nonzero numbers a,b,c.
https://math.stackexchange.com/questions/1579934/prove-that-frac1aa-ba-c-frac1bb-cb-a-frac1cc-ac-b
First, I'll mention an elementary way to finish the proof. Observe that this could be done by expanding the following product: f(c)=bc(b−c)−ac(a−c)+ab(a−b)−(a−b)(a−c)(b−c). At the end, you ...
What sort of particles corresponds to the (1,1/2) representation of the Lorentz group?
https://physics.stackexchange.com/q/439085
I think that my question wasn't actually well defined. For starters, when you restrict to the SO(3) subgroup of the (j_1, j_2) rep. of the Lorentz group, you get the j_1 \otimes j_2 rep of ...
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3 \frac{ 3 }{ 7 }
4 \frac{ 15 }{ 32 }
1 \frac{ 1 }{ 2 } +3 \frac{ 4 }{ 5 }
1 \frac{ 1 }{ 2 } -3 \frac{ 4 }{ 5 }
1 \frac{ 1 }{ 2 } \times 3 \frac{ 4 }{ 5 }
1 \frac{ 1 }{ 2 } \div 3 \frac{ 4 }{ 5 }
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