跳到主要内容
Microsoft
|
Math Solver
求解
玩
练习
下载
求解
练习
玩
游戏中心
乐趣 + 提高技能 = 赢！
主题
算术
平均值
模式
最大公因数
最小公倍数
操作顺序
分数
带分数
素因数分解
指数
激进分子
代数
合并喜欢的条款
变量求解
因子
展开
评估分数
线性方程组
二次方程
不等式
方程组
矩阵
三角学
简化
评价
图表
解方程
微积分
衍生物
积分
限制
几何计算器
三角函数计算器
微积分计算器
矩阵计算器
下载
游戏中心
乐趣 + 提高技能 = 赢！
主题
算术
平均值
模式
最大公因数
最小公倍数
操作顺序
分数
带分数
素因数分解
指数
激进分子
代数
合并喜欢的条款
变量求解
因子
展开
评估分数
线性方程组
二次方程
不等式
方程组
矩阵
三角学
简化
评价
图表
解方程
微积分
衍生物
积分
限制
几何计算器
三角函数计算器
微积分计算器
矩阵计算器
求解
代数
三角学
统计
微积分
矩阵
变数
列表
lcm(1%2C2%2C3%2C4%2C5)
求值
1
查看解决方案步骤
求解步骤
lcm(1%2C2%2C3%2C4%2C5)
找到所有表达式中的所有因式及其最高次幂。将这些因数的最高次幂相乘以获得最小公倍式。
1
因式分解
1
测验
lcm(1%2C2%2C3%2C4%2C5)
来自 Web 搜索的类似问题
Nate can buy T-shirts in packs of 5 for 11.60 or in packs of 2 for 6.50. How much money does he save by buying 10 T-shirts at the better price?
https://brainly.com/question/9011423
(Let's say 5=11.60 is A and 2=6.50 is B.)A = 23.20B = 32.50Nate saves 9.30 by.
Why don't all elements of an arithmetic progression divide the lcm of the start and step?
https://math.stackexchange.com/questions/212237/why-dont-all-elements-of-an-arithmetic-progression-divide-the-lcm-of-the-start
You’re looking at this statement in the Wikipedia article : If a formula involving integer variables, \mathbf{gcd}, \mathbf{lcm}, \le and \ge is true, then the formula obtained by switching \mathbf{gcd} ...
Number of item distributions in buckets of different sizes
https://math.stackexchange.com/questions/452901/number-of-item-distributions-in-buckets-of-different-sizes
Here the answer I gave in comments while this question was on Mathoverflow does probably belong as a proper answer, so I may as well reproduce it so that this question can be marked as answered and ...
Is f_1, f_2 and f_3 are linearly independent?
https://math.stackexchange.com/questions/2493438/is-f-1-f-2-and-f-3-are-linearly-independent
No, the correct answer is A. They don't for a basis of \mathcal{C}(\mathbb{R}). For instance, you cannot express the identity as a linear combination of your functions.
Prove that if LCMs are equal, then the numbers are equal too.
https://math.stackexchange.com/questions/2169008/prove-that-if-lcms-are-equal-then-the-numbers-are-equal-too
I assumed a and b were positive integers. We have \mathrm{lcm}(a,a+5) = \frac {a(a+5)}{\gcd(a,a+5)}, so that the given equality implies \frac {a(a+5)}{\gcd(a,a+5)} = \frac {b(b+5)}{\gcd(b,b+5)}. ...
Existence of two basis such that a linear operator could be associated to a fixed matrix
https://math.stackexchange.com/questions/1993669/existence-of-two-basis-such-that-a-linear-operator-could-be-associated-to-a-fixe
If M was representing T in some bases, its rank would be equal to the dimension of \operatorname{im}(T), which is 3. But actually M has rank 2, because the third column is the first one ...
更多结果
共享
复制
已复制到剪贴板
1
找到所有表达式中的所有因式及其最高次幂。将这些因数的最高次幂相乘以获得最小公倍式。
类似问题
lcm(12,16)
lcm(25,30)
lcm(3,4)
lcm(1,2,3,4,5)
lcm(20,45,10)
lcm(2,3,5,6,10)
回到顶部
