求解 tan^-1(1)=x | Microsoft Math Solver

求解 x 的值

x = \frac{200000000000000000}{3491012985643517} = 57\frac{1012259818319531}{3491012985643517} \approx 57.289961631

求解线性方程的步骤

\tan ^ { - 1 } ( 1 ) = x

对题中的三角函数求值

0.017455064928217585 ^ {-1} = x

计算 -1 的 0.017455064928217585 乘方，得到 \frac{200000000000000000}{3491012985643517}。

\frac{200000000000000000}{3491012985643517}=x

移项以使所有变量项位于左边。

x=\frac{200000000000000000}{3491012985643517}

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测验

Trigonometry

5 道与此类似的题目:

\tan ^ { - 1 } ( 1 ) = x

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\newcommand{\+}{^{\dagger}} \newcommand{\angles}[1]{\left\langle\, #1 \,\right\rangle} \newcommand{\braces}[1]{\left\lbrace\, #1 \,\right\rbrace} \newcommand{\bracks}[1]{\left\lbrack\, #1 \,\right\rbrack} \newcommand{\ceil}[1]{\,\left\lceil\, #1 \,\right\rceil\,} \newcommand{\dd}{{\rm d}} \newcommand{\down}{\downarrow} \newcommand{\ds}[1]{\displaystyle{#1}} \newcommand{\expo}[1]{\,{\rm e}^{#1}\,} \newcommand{\fermi}{\,{\rm f}} \newcommand{\floor}[1]{\,\left\lfloor #1 \right\rfloor\,} \newcommand{\half}{{1 \over 2}} \newcommand{\ic}{{\rm i}} \newcommand{\iff}{\Longleftrightarrow} \newcommand{\imp}{\Longrightarrow} \newcommand{\isdiv}{\,\left.\right\vert\,} \newcommand{\ket}[1]{\left\vert #1\right\rangle} \newcommand{\ol}[1]{\overline{#1}} \newcommand{\pars}[1]{\left(\, #1 \,\right)} \newcommand{\partiald}[3][]{\frac{\partial^{#1} #2}{\partial #3^{#1}}} \newcommand{\pp}{{\cal P}} \newcommand{\root}[2][]{\,\sqrt[#1]{\vphantom{\large A}\,#2\,}\,} \newcommand{\sech}{\,{\rm sech}} \newcommand{\sgn}{\,{\rm sgn}} \newcommand{\totald}[3][]{\frac{{\rm d}^{#1} #2}{{\rm d} #3^{#1}}} \newcommand{\ul}[1]{\underline{#1}} \newcommand{\verts}[1]{\left\vert\, #1 \,\right\vert} \newcommand{\wt}[1]{\widetilde{#1}} ...

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已复制到剪贴板

0.017455064928217585 ^ {-1} = x

对题中的三角函数求值

\frac{200000000000000000}{3491012985643517}=x

计算 -1 的 0.017455064928217585 乘方，得到 \frac{200000000000000000}{3491012985643517}。

x=\frac{200000000000000000}{3491012985643517}

移项以使所有变量项位于左边。

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