求解 g_5 的值 (复数求解)
\left\{\begin{matrix}g_{5}=\frac{\log_{5}\left(2\left(x-2\right)\right)+1}{9o\left(x-1\right)}\text{, }&x\neq 1\text{ and }o\neq 0\text{ and }x\neq 2\\g_{5}\in \mathrm{C}\text{, }&o=0\text{ and }x=\frac{21}{10}\end{matrix}\right.
求解 o 的值 (复数求解)
\left\{\begin{matrix}o=\frac{\log_{5}\left(2\left(x-2\right)\right)+1}{9g_{5}\left(x-1\right)}\text{, }&x\neq 1\text{ and }g_{5}\neq 0\text{ and }x\neq 2\\o\in \mathrm{C}\text{, }&g_{5}=0\text{ and }x=\frac{21}{10}\end{matrix}\right.
求解 g_5 的值
\left\{\begin{matrix}g_{5}=\frac{\log_{5}\left(2\left(x-2\right)\right)+1}{9o\left(x-1\right)}\text{, }&o\neq 0\text{ and }x>2\\g_{5}\in \mathrm{R}\text{, }&o=0\text{ and }x=\frac{21}{10}\end{matrix}\right.
求解 o 的值
\left\{\begin{matrix}o=\frac{\log_{5}\left(2\left(x-2\right)\right)+1}{9g_{5}\left(x-1\right)}\text{, }&g_{5}\neq 0\text{ and }x>2\\o\in \mathrm{R}\text{, }&g_{5}=0\text{ and }x=\frac{21}{10}\end{matrix}\right.
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