解 y (復數求解)
\left\{\begin{matrix}\\y=\frac{\sqrt{225x^{2}-420x+4}}{12}+\frac{3x}{4}+\frac{1}{6}\text{, }&\text{unconditionally}\\y=-\frac{\sqrt{225x^{2}-420x+4}}{12}+\frac{3x}{4}+\frac{1}{6}\text{, }&x\neq 0\end{matrix}\right.
解 x
\left\{\begin{matrix}\\x=\frac{\sqrt{225y^{2}-390y+361}}{12}-\frac{3y}{4}+\frac{19}{12}\text{, }&\text{unconditionally}\\x=-\frac{\sqrt{225y^{2}-390y+361}}{12}-\frac{3y}{4}+\frac{19}{12}\text{, }&y\neq 0\end{matrix}\right.
解 y
\left\{\begin{matrix}y=-\frac{\sqrt{225x^{2}-420x+4}}{12}+\frac{3x}{4}+\frac{1}{6}\text{, }&x\geq \frac{8\sqrt{3}+14}{15}\text{ or }\left(x\neq 0\text{ and }x\leq \frac{14-8\sqrt{3}}{15}\right)\\y=\frac{\sqrt{225x^{2}-420x+4}}{12}+\frac{3x}{4}+\frac{1}{6}\text{, }&x\geq \frac{8\sqrt{3}+14}{15}\text{ or }x\leq \frac{14-8\sqrt{3}}{15}\end{matrix}\right.
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示例
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\left[ \begin{array} { l l } { 2 } & { 3 } \\ { 5 } & { 4 } \end{array} \right] \left[ \begin{array} { l l l } { 2 } & { 0 } & { 3 } \\ { -1 } & { 1 } & { 5 } \end{array} \right]
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限制
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