z^2+7z eching

$$z ^ { 2 } + 7 z$$

Omil

$$z\left(z+7\right)$$

Yechim qadamlari

z omili.

$$z\left(z+7\right)$$

Kvadrat tenglamalaridan foydalanish qoidalari

Kvadrat koʻp tenglama bu orqali hisoblanadi: ax^{2}+bx+c=a\left(x-x_{1}\right)\left(x-x_{2}\right), bu yerda x_{1} va x_{2} ax^{2}+bx+c=0 kvadrat tenglamaning yechimlari.

$$z^{2}+7z=0$$

ax^{2}+bx+c=0 shaklidagi barcha tenglamalarni kvadrat formulasi bilan yechish mumkin: \frac{-b±\sqrt{b^{2}-4ac}}{2a}. Kvadrat formula ikki yechmni taqdim qiladi, biri ± qo'shish bo'lganda, va ikkinchisi ayiruv bo'lganda.

$$z=\frac{-7±\sqrt{7^{2}}}{2}$$

7^{2} ning kvadrat ildizini chiqarish.

$$z=\frac{-7±7}{2}$$

z=\frac{-7±7}{2} tenglamasini yeching, bunda ± musbat. -7 ni 7 ga qo'shish.

$$z=\frac{0}{2}$$

0 ni 2 ga bo'lish.

$$z=0$$

z=\frac{-7±7}{2} tenglamasini yeching, bunda ± manfiy. -7 dan 7 ni ayirish.

$$z=-\frac{14}{2}$$

-14 ni 2 ga bo'lish.

$$z=-7$$

ax^{2}+bx+c=a\left(x-x_{1}\right)\left(x-x_{2}\right) formulasi yordamida amalni hisoblang. x_{1} uchun 0 ga va x_{2} uchun -7 ga bo‘ling.

$$z^{2}+7z=z\left(z-\left(-7\right)\right)$$

p-\left(-q\right) shaklining barcha amallarigani p+q ga soddalashtiring.

$$z^{2}+7z=z\left(z+7\right)$$

Baholash

$$z\left(z+7\right)$$