z=f(xy) eching

$$z = f ( x y )$$

f uchun yechish

$$\left\{\begin{matrix}f=\frac{z}{xy}\text{, }&y\neq 0\text{ and }x\neq 0\\f\in \mathrm{R}\text{, }&\left(y=0\text{ or }x=0\right)\text{ and }z=0\end{matrix}\right,$$

Chiziqli tenglamalarni yechish bo'yicha qadamlar

Tomonlarni almashtirib, barcha oʻzgaruvchi shartlar chap tomonga oʻtkazing.

$$fxy=z$$

Tenglama standart shaklda.

$$xyf=z$$

Ikki tarafini xy ga bo‘ling.

$$\frac{xyf}{xy}=\frac{z}{xy}$$

xy ga bo'lish xy ga ko'paytirishni bekor qiladi.

$$f=\frac{z}{xy}$$

x uchun yechish

$$\left\{\begin{matrix}x=\frac{z}{fy}\text{, }&y\neq 0\text{ and }f\neq 0\\x\in \mathrm{R}\text{, }&\left(y=0\text{ or }f=0\right)\text{ and }z=0\end{matrix}\right,$$

Chiziqli tenglamalarni yechish bo'yicha qadamlar

Tomonlarni almashtirib, barcha oʻzgaruvchi shartlar chap tomonga oʻtkazing.

$$fxy=z$$

Tenglama standart shaklda.

$$fyx=z$$

Ikki tarafini fy ga bo‘ling.

$$\frac{fyx}{fy}=\frac{z}{fy}$$

fy ga bo'lish fy ga ko'paytirishni bekor qiladi.

$$x=\frac{z}{fy}$$