z=a-b/b+c eching

$$z = \frac { a - b } { b } + c$$

b uchun yechish

$$\left\{\begin{matrix}b=-\frac{a}{-z+c-1}\text{, }&a\neq 0\text{ and }z\neq c-1\\b\neq 0\text{, }&a=0\text{ and }z=c-1\end{matrix}\right,$$

Chiziqli tenglamalarni yechish bo'yicha qadamlar

b qiymati 0 teng bo‘lmaydi, chunki nolga bo‘lish mumkin emas. Tenglamaning ikkala tarafini b ga ko'paytirish.

$$zb=a-b+bc$$

b ni ikki tarafga qo’shing.

$$zb+b=a+bc$$

Ikkala tarafdan bc ni ayirish.

$$zb+b-bc=a$$

b'ga ega bo'lgan barcha shartlarni birlashtirish.

$$\left(z+1-c\right)b=a$$

Tenglama standart shaklda.

$$\left(z-c+1\right)b=a$$

Ikki tarafini z+1-c ga bo‘ling.

$$\frac{\left(z-c+1\right)b}{z-c+1}=\frac{a}{z-c+1}$$

z+1-c ga bo'lish z+1-c ga ko'paytirishni bekor qiladi.

$$b=\frac{a}{z-c+1}$$

b qiymati 0 teng bo‘lmaydi.

$$b=\frac{a}{z-c+1}\text{, }b\neq 0$$

a uchun yechish

$$a=b\left(z-c+1\right)$$

$$b\neq 0$$