y=sqrt{x*5} eching

$$y= \sqrt{ x \times 5 }$$

x uchun yechish

$$x=\frac{y^{2}}{5}$$

$$y\geq 0$$

Ildizli tenglamalarni yechish qadamlari

Tomonlarni almashtirib, barcha oʻzgaruvchi shartlar chap tomonga oʻtkazing.

$$\sqrt{x\times 5}=y$$

Tenglamaning ikkala taraf kvadratini chiqarish.

$$5x=y^{2}$$

Ikki tarafini 5 ga bo‘ling.

$$\frac{5x}{5}=\frac{y^{2}}{5}$$

5 ga bo'lish 5 ga ko'paytirishni bekor qiladi.

$$x=\frac{y^{2}}{5}$$

x uchun yechish (complex solution)

$$x=\frac{y^{2}}{5}$$

$$arg(y)<\pi \text{ or }y=0$$

y uchun yechish (complex solution)

$$y=\sqrt{5x}$$

y uchun yechish

$$y=\sqrt{5x}$$

$$x\geq 0$$