y=sqrt{4-7x} eching

$$y= \sqrt{ 4-7x }$$

x uchun yechish

$$x=\frac{4-y^{2}}{7}$$

$$y\geq 0$$

Ildizli tenglamalarni yechish qadamlari

Tomonlarni almashtirib, barcha oʻzgaruvchi shartlar chap tomonga oʻtkazing.

$$\sqrt{4-7x}=y$$

Tenglamaning ikkala taraf kvadratini chiqarish.

$$-7x+4=y^{2}$$

Tenglamaning ikkala tarafidan 4 ni ayirish.

$$-7x+4-4=y^{2}-4$$

O‘zidan 4 ayirilsa 0 qoladi.

$$-7x=y^{2}-4$$

Ikki tarafini -7 ga bo‘ling.

$$\frac{-7x}{-7}=\frac{y^{2}-4}{-7}$$

-7 ga bo'lish -7 ga ko'paytirishni bekor qiladi.

$$x=\frac{y^{2}-4}{-7}$$

y^{2}-4 ni -7 ga bo'lish.

$$x=\frac{4-y^{2}}{7}$$

x uchun yechish (complex solution)

$$x=\frac{4-y^{2}}{7}$$

$$arg(y)<\pi \text{ or }y=0$$

y uchun yechish

$$y=\sqrt{4-7x}$$

$$x\leq \frac{4}{7}$$