y=1-x/x-3 eching

$$y= \frac{ 1-x }{ x-3 }$$

x uchun yechish

$$x=\frac{3y+1}{y+1}$$

$$y\neq -1$$

Chiziqli tenglamalarni yechish bo'yicha qadamlar

x qiymati 3 teng bo‘lmaydi, chunki nolga bo‘lish mumkin emas. Tenglamaning ikkala tarafini x-3 ga ko'paytirish.

$$y\left(x-3\right)=1-x$$

y ga x-3 ni ko'paytirish orqali distributiv xususiyatdan foydalanish.

$$yx-3y=1-x$$

x ni ikki tarafga qo’shing.

$$yx-3y+x=1$$

3y ni ikki tarafga qo’shing.

$$yx+x=1+3y$$

x'ga ega bo'lgan barcha shartlarni birlashtirish.

$$\left(y+1\right)x=1+3y$$

Tenglama standart shaklda.

$$\left(y+1\right)x=3y+1$$

Ikki tarafini y+1 ga bo‘ling.

$$\frac{\left(y+1\right)x}{y+1}=\frac{3y+1}{y+1}$$

y+1 ga bo'lish y+1 ga ko'paytirishni bekor qiladi.

$$x=\frac{3y+1}{y+1}$$

x qiymati 3 teng bo‘lmaydi.

$$x=\frac{3y+1}{y+1}\text{, }x\neq 3$$

y uchun yechish

$$y=-\frac{x-1}{x-3}$$

$$x\neq 3$$